On a certain day, there were 104 pennies in jar A and 20 pennies in jar B. On each subsequent day, 3 pennies were removed from jar A and 4 pennies were added to jar B until the jars had the same number of pennies. On how many days were pennies removed from jar A?
It took 12 days for pennies to be removed from jar A until both jars had the same number of pennies.
Initially, jar A has 104 pennies and jar B has 20 pennies. Each day, 3 pennies are removed from jar A and 4 pennies are added to jar B. After 12 days, both jars will contain an equal number of pennies.
If pennies were removed for only 8 days, jar A would have 104 - (3 * 8) = 88 pennies, and jar B would have 20 + (4 * 8) = 52 pennies. The two jars would not have the same amount, indicating that 8 days is insufficient.
After 10 days, jar A would have 104 - (3 * 10) = 74 pennies, while jar B would contain 20 + (4 * 10) = 60 pennies. This shows that 10 days is also not enough time for the amounts in both jars to equalize.
After 12 days, jar A would have 104 - (3 * 12) = 68 pennies, and jar B would have 20 + (4 * 12) = 68 pennies as well. Both jars indeed have the same amount at this point, confirming that 12 days is the correct answer.
If 14 days were considered, jar A would be left with 104 - (3 * 14) = 56 pennies, while jar B would have 20 + (4 * 14) = 76 pennies. This indicates that 14 days exceeds the necessary time for both jars to have the same number of pennies.
After 16 days, jar A would contain 104 - (3 * 16) = 40 pennies, and jar B would have 20 + (4 * 16) = 84 pennies. The imbalance in the number of pennies demonstrates that 16 days is far too many for the jars to equalize.
The calculation shows that it takes exactly 12 days for both jars to equalize their penny counts, with jar A going from 104 to 68 pennies and jar B from 20 to 68 pennies. Other options either do not allow the jars to equalize or overshoot the necessary days, confirming that 12 days is indeed the correct duration for this scenario.
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