Consider the dihybrid cross, YySs x YySs, where Y refers to yellow fur, y refers to white fur, S refers to short fur, and s refers to long fur. Capitalized letters refer to dominant traits, and lowercase letters refer to recessive traits. How many offspring have white, long fur?
Only 1 offspring will have white, long fur from the dihybrid cross YySs x YySs.
In this dihybrid cross, the recessive traits of white fur (yy) and long fur (ss) can only manifest when both alleles are recessive. The probability of obtaining these traits in the offspring is calculated through the Punnett square, resulting in only one combination that yields white, long fur.
This choice is correct because, when conducting a dihybrid cross of YySs x YySs, the resultant offspring can only produce one combination (yyss) that expresses both recessive traits of white fur and long fur. The distribution of traits through the Punnett square confirms this outcome.
This option is incorrect, as it overestimates the number of combinations that can result in white, long fur. The combinations needed to express both recessive traits (yy and ss) occur in only one specific instance out of the total 16 possible combinations in the Punnett square.
This choice is also incorrect, as it suggests a higher outcome than actually possible. The calculation shows that only one of the 16 combinations results in white, long fur, meaning eight offspring cannot express these traits simultaneously.
This selection is incorrect as well, as it implies an even higher figure than the previous incorrect answers. The genetics of the dihybrid cross clearly indicate that there is only one possible genotype (yyss) that results in white, long fur among the offspring.
In summary, the dihybrid cross YySs x YySs results in a specific ratio of offspring phenotypes, where only 1 out of 16 offspring will exhibit the combination of white fur and long fur. Understanding the inheritance patterns and recessive traits is crucial for accurate predictions in genetic crosses.
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