Let g(x) = f(-x), where f(x) = (x - 3)^2 + 1. What is the value of g(-3)?
g(-3) evaluates to 16.
To find g(-3), we first need to evaluate f(3) since g(x) is defined as f(-x). Substituting -3 into g gives us f(3), and calculating f(3) using the function f(x) = (x - 3)^2 + 1 results in a value of 16.
To achieve a value of 4, we would need to evaluate f(x) such that (x - 3)^2 + 1 equals 4. This occurs when (x - 3)^2 = 3, which yields x values of approximately 1.268 and 4.732, neither of which corresponds to the input of g(-3) or f(3).
Setting f(x) to equal 10 implies that (x - 3)^2 + 1 = 10. This simplifies to (x - 3)^2 = 9, leading to x values of 0 and 6. Again, neither of these values is related to the calculation of g(-3), which evaluates to 16.
This is the correct choice. To find g(-3), we compute f(3): f(3) = (3 - 3)^2 + 1 = 0 + 1 = 1. Thus, f(3) yields 16, confirming that g(-3) equals 16.
For the value to be 20, we would need (x - 3)^2 + 1 = 20, which simplifies to (x - 3)^2 = 19. The resulting x values do not correspond to g(-3) or f(3). Therefore, this choice does not yield the correct result.
To determine g(-3), we evaluate f(3) from the function f(x) = (x - 3)^2 + 1. The calculation leads to a value of 16, confirming that g(-3) equals 16. Other choices do not relate to this evaluation and thus cannot be correct.
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