Which output results from the given algorithm?
d = 6
n = 61
c = 0
while n >= d
c = c + 1
n = n - d
Put c to output

Rationale

11 is the output from the given algorithm.

The algorithm repeatedly subtracts the value of d (6) from n (61) until n is less than d. Each subtraction increments the counter c, which ultimately determines how many times d can be subtracted from n before the condition fails.

A (10) YOUR ANSWER

If the output were 10, it would imply that d was subtracted from n a total of 10 times. However, 10 subtractions of 6 (which equals 60) would leave n at 1, which is still greater than 0 but does not account for the final increment of c. Therefore, 10 is not a valid output.

B (11) CORRECT

Starting with n = 61 and subtracting d (6) repeatedly produces the following: 61 - 6 = 55, 55 - 6 = 49, 49 - 6 = 43, 43 - 6 = 37, 37 - 6 = 31, 31 - 6 = 25, 25 - 6 = 19, 19 - 6 = 13, 13 - 6 = 7, and 7 - 6 = 1. After 10 subtractions, n is 1, which leads to one more increment of c before exiting the loop. Thus, c equals 11, confirming this as the correct output.

C (15) YOUR ANSWER

An output of 15 would suggest that d was subtracted from n 15 times. However, with d = 6, 15 subtractions would amount to 90, which exceeds the initial value of n (61). Therefore, 15 is not a feasible output.

D (16) YOUR ANSWER

Similar to choice C, an output of 16 would require 16 subtractions of 6. This results in 96, which again surpasses n's initial value of 61. Hence, 16 cannot be the correct output.

Conclusion

The algorithm processes n by subtracting d iteratively until n is less than d, counting each iteration. The correct output is 11, as established by the algorithm's looping mechanism. All other choices either miscalculate the number of iterations or fail to recognize the constraints set by the initial values of n and d.

Which output results from the given algorithm? d = 6 n = 61 c = 0 while n >= d c = c + 1 n = n - d Put c to output

11 is the output from the given algorithm.

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Which output results from the given algorithm?
d = 6
n = 61
c = 0
while n >= d
c = c + 1
n = n - d
Put c to output