Which output results from the following pseudocode?
x = 5
do
x = x + 4
while x < 18
Put x to output:
21 is the output that results from the given pseudocode.
The pseudocode initializes `x` to 5 and then enters a loop that increments `x` by 4 as long as `x` is less than 18. By the time the loop completes, `x` will have been incremented to 21, which is the final output.
The output 9 would suggest that the loop executed only once, incrementing `x` from 5 to 9. However, the condition `x < 18` is still satisfied, meaning the loop would continue to run. Therefore, 9 cannot be the output since the loop performs multiple iterations.
The value 16 could be thought to result from two increments of 4, starting from 5 (5 + 4 + 4 = 16). However, after reaching 16, the loop condition `x < 18` holds true, so the loop would execute one more time, resulting in `x` being incremented to 20, thus making 16 an invalid output.
After starting with `x` as 5, the loop adds 4 repeatedly until `x` is no longer less than 18. The increments occur as follows: 5 → 9 → 13 → 17 → 21. Once `x` reaches 21, the loop terminates because 21 is not less than 18. Therefore, 21 is the correct output.
The output 25 would imply that the loop continued beyond the stopping condition. Since the loop only continues while `x < 18`, reaching 25 is impossible within the defined logic, as `x` would have stopped at 21 before reaching a value of 25.
In this pseudocode, the incrementing process loops until the condition fails, resulting in `x` reaching 21 after several increments from the initial value of 5. Options A, B, and D incorrectly interpret the loop's behavior or conditions, while C correctly identifies the final output after the loop concludes.
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