The number of different groups of 2 kittens that can be chosen from a litter of 8 kittens, Quantity A. The number of different groups of 6 puppies that can be chosen from a litter of 6 puppies, Quantity B
Quantity A is greater.
To find the number of different groups of kittens and puppies, we use the combination formula, which calculates how many ways we can choose a subset from a larger set without regard to the order of selection. The number of ways to choose 2 kittens from 8 is greater than the number of ways to choose 6 puppies from 6.
Calculating the combinations, the number of ways to choose 2 kittens from 8 is given by \( \binom{8}{2} = \frac{8!}{2!(8-2)!} = \frac{8 \times 7}{2 \times 1} = 28 \). In contrast, the number of ways to choose 6 puppies from 6 is \( \binom{6}{6} = 1 \). Thus, Quantity A (28) is indeed greater than Quantity B (1).
For Quantity B, the only way to choose all 6 puppies from a total of 6 is one way, resulting in a count of 1. Since Quantity A is 28, this choice incorrectly suggests that Quantity B can outnumber Quantity A, which it cannot.
This option states that both quantities are the same, which is incorrect as the calculations show that Quantity A equals 28 while Quantity B equals 1. Therefore, they are not equal.
This option implies uncertainty in the comparison of the two quantities, which is not the case. The values derived from the combinations provide a clear relationship, showing that Quantity A is definitively greater than Quantity B.
In summary, by employing the combination formula, we find that the number of ways to select 2 kittens from 8 is significantly greater than the only way to select all 6 puppies from 6. Thus, Quantity A exceeds Quantity B, affirming that the relationship is clearly established.
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