Solve the following equation for x. 9/(2x) = 27
x = 1/6
To solve the equation \( \frac{9}{2x} = 27 \), we can manipulate the equation to isolate \( x \). By multiplying both sides by \( 2x \) and then simplifying, we find that \( x \) must equal \( \frac{1}{6} \).
This choice suggests that \( x \) equals 6, which leads to a different value when substituting back into the original equation. Substituting 6 into \( \frac{9}{2x} \) results in \( \frac{9}{12} = 0.75 \), which does not equal 27, proving that this is incorrect.
While this simplifies to \( x = 3 \), substituting 3 back into the original equation yields \( \frac{9}{6} = 1.5 \), which is also not equal to 27. Thus, this choice does not satisfy the equation.
This choice claims \( x \) equals 54, which significantly overshoots the correct solution. Substituting 54 into the original equation gives \( \frac{9}{108} = \frac{1}{12} \), which is incorrect since it does not equal 27.
The only value that solves the equation \( \frac{9}{2x} = 27 \) is \( x = \frac{1}{6} \). All other choices fail to satisfy the equation when substituted back, confirming that \( x = 1/6 \) is the only viable solution. This process highlights the importance of correctly isolating variables and validating solutions through substitution.
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