Solve for X: 3(X+2)=21
The solution to the equation 3(X+2)=21 is X = 5.
To solve the equation, first distribute the 3 on the left side of the equation to get 3X + 6 = 21. Then, subtract 6 from both sides to isolate the term with X, resulting in 3X = 15. Finally, divide both sides by 3 to solve for X, yielding X = 5.
If we substitute X = -5 into the equation, it results in 3(-5+2) = 3(-3) = -9, which does not equal 21. Therefore, X = -5 is not the solution.
Substituting X = -6.33333 into the equation, we get 3(-6.33333+2) = 3(-4.33333) = -13, which also does not equal 21. Therefore, X = -6.33333 is not the solution.
Substituting X = -9 into the equation, we get 3(-9+2) = 3(-7) = -21, which does not equal 21. Therefore, X = -9 is not the solution.
If we substitute X = 5 into the equation, it results in 3(5+2) = 3(7) = 21, which equals 21. Therefore, X = 5 is the correct solution.
The equation 3(X+2)=21 is solved by the process of distribution, subtraction, and division. After performing these operations, it is found that X = 5 is the correct solution. The other choices, X = -5, X = -6.33333, and X = -9, do not satisfy the equation when substituted for X.
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