One person pushes on a motionless box in the right direction with a force of 15 N. Another person pushes on the box in the left direction with a force of 5 N. Assuming that the static friction force is negligible, what is the result?
The box moves to the right.
The net force acting on the box is the difference between the forces applied in opposite directions. With a force of 15 N to the right and 5 N to the left, the resulting force is 10 N to the right, causing the box to move in that direction.
This choice would only be valid if the forces acting on the box were equal and opposite, resulting in a net force of zero. However, since the force to the right (15 N) is greater than the force to the left (5 N), the box cannot remain stationary and will instead move to the right.
The forces mentioned in the question are horizontal, with one person pushing to the right and the other to the left. There are no vertical forces indicated; thus, the box cannot move upward based on the information provided.
While there is a force acting to the left (5 N), it is significantly weaker than the force applied to the right (15 N). The net force of 10 N to the right means the box will not move left but rather in the opposite direction.
With a net force of 10 N to the right, the box will indeed move in that direction. This choice accurately reflects the outcome based on the principles of force and motion, where the larger force dominates and determines the movement of the object.
In this scenario, the combined forces acting on the box lead to a net force that dictates its motion. Since the force to the right is greater than the force to the left, the box will move to the right with a resultant force of 10 N. Understanding these concepts of net force and direction is crucial in analyzing motion effectively.
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