In a city's public transportation system, the distribution of commuters by mode of transport is as follows: 40% use buses, 25% use trains, 20% use bicycles, 10% walk, and 5% use other means of transportation. What is the probability that a randomly selected commuter uses either a bus or a train?
The probability that a randomly selected commuter uses either a bus or a train is 65%.
To find this probability, we simply add the percentages of commuters using buses (40%) and trains (25%). Thus, 40% + 25% equals 65%, which represents the probability of a randomly selected commuter using either mode of transport.
This choice incorrectly suggests a much lower combined probability. The calculation of 30% does not accurately account for the proportions of commuters who use buses and trains, which together sum to 65%.
Selecting 45% reflects an underestimation of the combined percentage of bus and train commuters. This figure disregards the total contribution of both modes, as the correct calculation shows that their combined probability is significantly higher at 65%.
A probability of 50% again fails to capture the accurate total of commuters using either buses or trains. This figure does not include the full contribution of bus and train users, leading to a miscalculation of the actual probability.
This choice correctly represents the total probability, calculated by adding the 40% of bus users to the 25% of train users. Therefore, the correct answer reflects the accurate summation of these two groups.
In summary, the probability of a randomly selected commuter using either a bus or a train in the city's public transportation system is 65%. This is derived from the direct addition of the respective percentages of commuters using each mode. All other options miscalculate this probability by failing to incorporate the correct figures from the data provided.
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