During an experiment a buzzer beeped once every quarter hour. If the first beep was at 3:15, what was the time at the 18th beep?
The time at the 18th beep was 7:30.
The buzzer beeps once every quarter hour, which is equivalent to 15 minutes. Therefore, to find the time of the 18th beep, we calculate 15 minutes multiplied by 17 (since the first beep occurs at 3:15) and add that to the initial time.
This option implies that the 18th beep occurs 3 hours and 15 minutes after the first beep. Since the first beep is at 3:15, adding 3 hours and 15 minutes would result in 6:30. However, this does not account for the total time duration needed to reach the 18th beep.
This option suggests that the 18th beep is at 7:00, which would require the total elapsed time to be 3 hours and 45 minutes from the initial beep at 3:15. This is incorrect as it does not accurately reflect the timing of the beeping sequence.
Choosing 7:15 would indicate that the 18th beep occurs at 4 hours after the first beep. This is incorrect because it fails to account for the 17 additional 15-minute intervals that need to be added to the initial time.
This is the correct answer, as it accurately represents the time at the 18th beep. Starting from 3:15, 17 intervals of 15 minutes each lead to a total of 255 minutes (or 4 hours and 15 minutes), resulting in a final time of 7:30.
To determine the time of the 18th beep, one must add the total duration of 255 minutes to the starting time of 3:15. This calculation confirms that the 18th beep occurs at 7:30, making it the only correct choice among the options provided. Understanding the relationship between time intervals and cumulative durations is essential for solving such problems accurately.
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