A single ball is drawn from an opaque bag that contains red, blue, and green balls. The probability of drawing a red ball is 0.3, and the probability of drawing a blue ball is 0.6. What is the probability of drawing a green ball?
The probability of drawing a green ball is 0.1.
In probability, the sum of all possible outcomes must equal 1. Given that the probabilities of drawing a red and a blue ball are 0.3 and 0.6 respectively, the probability of drawing a green ball can be calculated by subtracting the sum of the other probabilities from 1: 1 - (0.3 + 0.6) = 0.1.
This choice is correct as it accurately reflects the remaining probability after accounting for the red and blue balls. With the probabilities of red and blue adding up to 0.9, the leftover probability for drawing a green ball is indeed 0.1.
This option incorrectly suggests that there is a 30% chance of drawing a green ball. However, since the total probability of red and blue balls is 0.9, this would exceed the total probability limit if combined with the other colors. Therefore, this choice does not satisfy the probability requirement.
Choosing 0.5 implies that half of the outcomes are green, which would also contradict the total probability rule. Given the other two balls already account for 0.9, this choice cannot be correct as it would require the total to exceed 1.
This choice suggests that 90% of the outcomes are green, which is impossible given that the probabilities of red and blue already total 0.9. As such, this option contradicts the foundational principle of probability that all outcomes must sum to 1.
The calculation of the probability for drawing a green ball reveals that it is 0.1, derived from the total probabilities of red and blue balls. Choices B, C, and D misinterpret the constraints of probability, indicating a misunderstanding of how probabilities must sum to unity. Thus, the only valid choice is A, reflecting the correct probability for drawing a green ball.
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