A prescription calls for 30 mL of a 5% w/v solution. How many grams of active ingredient are required?
1.5 grams of active ingredient are required for a 30 mL of a 5% w/v solution.
To find the amount of active ingredient in grams, we use the formula for weight/volume percentage, which states that a 5% w/v solution contains 5 grams of solute per 100 mL of solution. Thus, for 30 mL, we calculate the amount of solute needed.
This choice represents a miscalculation of the required grams. A 5% w/v solution has 5 grams of active ingredient per 100 mL, which means for 30 mL, the amount cannot be as low as 0.15 grams. The correct calculation shows that 1.5 grams is needed.
This is the correct calculation. A 5% w/v solution contains 5 grams of the active ingredient in 100 mL. Therefore, for 30 mL, the calculation is (5 grams/100 mL) * 30 mL = 1.5 grams.
This choice indicates a misunderstanding of the percentage concentration. It suggests that for 30 mL of a 5% solution, there would be 15 grams of active ingredient, which is incorrect. The calculation shows that only 1.5 grams is needed.
This choice is significantly higher than the actual requirement. A 5% w/v solution does not contain 150 grams in 30 mL; it instead contains only 1.5 grams. This choice reflects a fundamental error in understanding the conversion from percentage concentration to grams.
In summary, the calculation for a 5% w/v solution shows that 1.5 grams of active ingredient are needed for a 30 mL preparation. The other options present incorrect calculations based on misunderstandings of weight/volume percentage and its application to solution preparation. Understanding the relationship between percentage concentration and the volume of solution is crucial for accurate dosing in pharmaceutical contexts.
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