What volume, in mL, of morphine sulfate that comes in 10 mL vials at a concentration of 5 mg/mL will be needed to fill an order for 25 mg?

Rationale

5 mL of morphine sulfate is needed to fill an order for 25 mg.

To determine the required volume for a 25 mg order from a solution with a concentration of 5 mg/mL, we divide the desired dose by the concentration: 25 mg ÷ 5 mg/mL = 5 mL.

A (1) YOUR ANSWER

Choosing 1 mL would provide only 5 mg of morphine sulfate (1 mL × 5 mg/mL), which is insufficient to meet the order of 25 mg. This option does not meet the required dosage and is incorrect.

B (2) YOUR ANSWER

If 2 mL is selected, it would yield only 10 mg of morphine sulfate (2 mL × 5 mg/mL). This amount is still far below the required 25 mg, making this option inadequate for fulfilling the order.

C (3) YOUR ANSWER

Selecting 3 mL results in a total of 15 mg of morphine sulfate (3 mL × 5 mg/mL). This volume is still short of the 25 mg needed, thus failing to satisfy the dosage requirement outlined in the order.

D (5) CORRECT

This option provides exactly 25 mg of morphine sulfate (5 mL × 5 mg/mL), which matches the order perfectly. It is the correct choice as it delivers the precise amount needed.

Conclusion

To fill an order for 25 mg of morphine sulfate from a solution at 5 mg/mL concentration, 5 mL of the solution is necessary. All other options fail to provide the required dosage, underscoring the importance of accurately calculating volume based on concentration and desired dosage.

What volume, in mL, of morphine sulfate that comes in 10 mL vials at a concentration of 5 mg/mL will be needed to fill an order for 25 mg?

5 mL of morphine sulfate is needed to fill an order for 25 mg.

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