Train A traveled 1603 miles from Seattle, Washington, to Tucson, Arizona, in 37 hours. Train B traveled 1090 miles from Portland, Oregon, to San Diego, California, in 24 hours. Which of the following statements is true?
Train B traveled at a greater average speed.
To find the average speed of each train, we divide the distance traveled by the time taken. Train A's average speed is approximately 43.3 miles per hour, while Train B's average speed is about 45.4 miles per hour. Therefore, Train B indeed has the higher average speed.
Train A's average speed is calculated as 1603 miles divided by 37 hours, resulting in approximately 43.3 miles per hour. This speed is lower compared to Train B's average speed, confirming that Train A did not exceed Train B in terms of average velocity.
Train B's average speed is determined to be 1090 miles divided by 24 hours, yielding approximately 45.4 miles per hour. This figure exceeds Train A's average speed, confirming that Train B indeed traveled faster on average.
The average speeds of the two trains are distinctly different, with Train A at 43.3 miles per hour and Train B at 45.4 miles per hour. Thus, they cannot be classified as traveling at equal speeds, as the calculations clearly show a difference.
While it's true that the distances traveled by the two trains are different, average speed can still be computed from distance and time regardless of the distance. Therefore, this statement is misleading, as the comparison of their average speeds is indeed possible and has been conducted.
In comparing the average speeds of Train A and Train B, it becomes clear that Train B, with an average speed of approximately 45.4 miles per hour, outpaces Train A, which averages around 43.3 miles per hour. The analysis demonstrates that average speed can be effectively compared even when distances differ, allowing for a clear identification of which train traveled faster.
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