Students at a local middle school are selling candy bars for a fund-raiser. The candy bars come packaged in cases of 60 bars, and the school makes a 0.75 profit from each candy bar sold. How many cases of candy bars need to be sold for the school to make a profit of 900?
20 cases of candy bars need to be sold for the school to make a profit of 900.
To determine how many cases must be sold, we first calculate the total profit from selling one case, which is 60 bars multiplied by a profit of $0.75 per bar, resulting in $45 per case. Dividing the desired profit of $900 by the profit per case ($45) gives us 20 cases.
Selling 8 cases would yield a profit of 8 cases × $45 per case = $360. This amount is significantly less than the required profit of $900, making this option incorrect.
If 12 cases are sold, the profit would be 12 cases × $45 per case = $540. Although this is a higher profit than option A, it still does not meet the target of $900, thus making this choice incorrect as well.
Selling 20 cases generates a profit of 20 cases × $45 per case = $900. This matches exactly the target profit needed, confirming that this is the correct answer.
If 40 cases are sold, the resulting profit would be 40 cases × $45 per case = $1,800. While this amount exceeds the target of $900, the question specifically asks for the minimum number of cases needed to reach the desired profit, making this option unnecessarily high.
To achieve a profit of $900 from selling candy bars, students must sell 20 cases, as this amount generates the exact profit required. Other options either fall short of the target or exceed it without being necessary, emphasizing the need for precise calculations in fundraising efforts.
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