Line k has slope -2 and passes through point (3, -1). Quantity A: The x-intercept of line k, Quantity B: The y-intercept of line k
Quantity B is greater.
To find the intercepts of line k with a slope of -2 that passes through the point (3, -1), we can determine that the y-intercept will be greater than the x-intercept. This is because the line's negative slope indicates it will cross the y-axis at a higher value than it does the x-axis.
The x-intercept can be calculated by setting y to 0 in the line equation \( y = -2x + b \). Substituting the known point (3, -1) allows us to find the y-intercept (b) as 5. Setting y to 0 gives an x-intercept of 2. Since the y-intercept (5) is greater than the x-intercept (2), this option is incorrect.
As established, the y-intercept is determined to be 5, while the x-intercept is found to be 2. Since 5 is indeed greater than 2, this choice accurately reflects the relationship between the two quantities.
For the two quantities to be equal, both intercepts would need to have the same value. However, we calculated the y-intercept as 5 and the x-intercept as 2, demonstrating they are not equal. Therefore, this option is incorrect.
The information provided is sufficient to calculate both intercepts explicitly. We have determined that the y-intercept is 5 and the x-intercept is 2. Thus, this choice is also incorrect, as the relationship can be clearly established.
The calculated intercepts of line k illustrate that the y-intercept (5) is greater than the x-intercept (2). This definitive relationship confirms that Quantity B is greater than Quantity A, demonstrating that the slope and the point through which the line passes provide enough information to determine the intercepts accurately.
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