In an experiment, a student tests three unknown fluids with the following measurements: Fluid A: m=2060g, V=2000mL, Fluid B: m=672g, V=850mL, and Fluid C: m=990g, V=1100mL. Arrange the liquids in the correct order of how they would separate in a beaker from bottom to top.
Fluid B, C, A will separate in a beaker from bottom to top.
The order of separation of the fluids in a beaker is determined by their densities, calculated as mass divided by volume. Fluid B has the highest density, followed by Fluid C, and finally Fluid A with the lowest density, leading to the arrangement from bottom to top.
This arrangement is incorrect because it places Fluid A, which has the lowest density, at the bottom. Fluid A's density of 1.03 g/mL is less than that of both Fluid B and Fluid C, meaning it would float above them in the beaker.
Fluid B is the densest at 0.79 g/mL, followed by Fluid C at 0.90 g/mL, and Fluid A at 1.03 g/mL. This correct order reflects their densities, with the densest fluid (B) settling at the bottom and the least dense (A) floating on top.
In this arrangement, Fluid C is incorrectly placed at the bottom despite being less dense than Fluid B. Fluid C's density of 0.90 g/mL should position it above Fluid B, which is denser at 0.79 g/mL.
This option also misplaces Fluid A, placing it above Fluid B. Since Fluid A is the least dense, it cannot be below Fluid B, which has a higher density. Therefore, this arrangement does not accurately reflect the separation based on density.
The arrangement of fluids in a beaker is dictated by their densities, with denser fluids sinking below less dense ones. In this case, Fluid B has the highest density, followed by Fluid C, and Fluid A has the lowest density, confirming the correct order of separation as B, C, A from bottom to top. Understanding density is crucial in predicting how different substances will behave when mixed.
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