If 250 mL of 10% methyl salicylate in alcohol is diluted to 1000 mL, what will be the percentage strength of the final volume?
The percentage strength of the final volume will be 2.50%.
When 250 mL of a 10% solution is diluted to 1000 mL, the concentration decreases as the volume increases due to the added solvent. This dilution can be calculated using the formula: C1V1 = C2V2, where C is concentration and V is volume.
This option represents a significantly lower concentration than what occurs in the dilution process. The calculation shows that the concentration does not drop to such a low percentage, as 0.25% would imply an extreme dilution beyond what is actually performed.
This is the correct choice, as when 250 mL of a 10% solution is diluted to 1000 mL, the concentration of methyl salicylate becomes 2.50%. Using the dilution formula: (10%)(250 mL) = (C2)(1000 mL), we find C2 = 2.50%.
This option indicates no change in concentration, which is incorrect. The original 10% solution cannot remain at this percentage after being diluted to a larger total volume of 1000 mL. Dilution inherently reduces the concentration of the solute.
This choice suggests an increase in concentration, which is not possible during a dilution process. Diluting a solution will always result in a lower concentration, thereby making 25% an impossible outcome in this scenario.
In summary, diluting a 250 mL solution of 10% methyl salicylate to a final volume of 1000 mL results in a new concentration of 2.50%. This demonstrates the fundamental concept of dilution, where increasing the volume of solvent decreases the solute concentration proportionately. Thus, understanding dilution calculations is essential in preparing solutions in various scientific and practical applications.
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