How many of the 9 orbital objects listed in the table above are at a distance from the Sun less than the average (arithmetic mean) distance from the Sun of the 9 orbital objects?

If seven objects were at a distance less than the average, it would imply that only two objects are further from the Sun, which contradicts the concept of an average because more than half of the objects being below the average is mathematically impossible.

Selecting five objects as being closer to the Sun than the average would mean that four are further away. This would still allow for the possibility of a sixth object being close enough to shift the average, making it unlikely that only five can be below the mean distance.

With only four objects below the average, there would be five that are above it. This scenario does not align with the calculated average distance, as it would suggest a significant imbalance between the distances of the objects.

If only three objects are at a distance less than the average, it indicates that six objects would be further away. This would skew the average significantly higher, making it improbable for only three to be below the mean.