How many mL of 0.1 M NaOH are needed to completely neutralize 10 mL of 0.2 M H₂SO₄?
40 mL of 0.1 M NaOH are needed to completely neutralize 10 mL of 0.2 M H₂SO₄.
To determine the volume of NaOH required for neutralization, we first calculate the moles of H₂SO₄ present in the solution. Each mole of H₂SO₄ reacts with two moles of NaOH, meaning that the stoichiometric ratio must be considered when performing the calculations.
This choice reflects a misunderstanding of the stoichiometry involved in the neutralization reaction. The amount of NaOH calculated here is insufficient to react with the entire amount of H₂SO₄, as 5 mL of 0.1 M NaOH only provides 0.005 moles, which is not enough to neutralize the required moles of acid.
Selecting 10 mL of NaOH still falls short of what is necessary for complete neutralization. This volume would provide only 0.01 moles of NaOH, which is still inadequate to fully react with the 0.02 moles of H₂SO₄ present, as twice the amount of NaOH is needed due to the 1:2 ratio in the reaction.
While 20 mL of 0.1 M NaOH provides 0.02 moles of NaOH, it is still incorrect because it matches the quantity of moles of H₂SO₄ but fails to account for the two moles of NaOH needed per mole of H₂SO₄. Thus, this amount is still insufficient for complete neutralization.
This is the correct choice. Using 40 mL of 0.1 M NaOH provides 0.04 moles of NaOH, which corresponds perfectly to the 0.02 moles of H₂SO₄ present, fulfilling the requirement of two moles of NaOH for every mole of H₂SO₄ for complete neutralization.
To neutralize 10 mL of 0.2 M H₂SO₄, 40 mL of 0.1 M NaOH is required, based on the stoichiometry of the reaction. Each mole of sulfuric acid necessitates two moles of sodium hydroxide for complete neutralization, leading to the conclusion that the necessary volume of NaOH must be calculated accordingly to ensure a complete reaction.
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