A prescription calls for 30 mL of a 5% w/v solution. How many grams of active ingredient are required?

Rationale

1.5 grams of active ingredient are required.

To find the amount of active ingredient in a 5% w/v solution, we calculate 5% of 30 mL, which equals 1.5 grams. This percentage indicates that there are 5 grams of solute in every 100 mL of solution, allowing us to determine the required mass for the specified volume.

A (0.15) YOUR ANSWER

This choice incorrectly suggests a significantly lower amount of active ingredient. Calculating 5% of 30 mL yields 1.5 grams, not 0.15 grams. This value does not reflect the correct application of the percentage formula.

B (1.5) CORRECT

This is the correct answer, as it accurately represents 5% of 30 mL. The calculation involves multiplying 30 mL by 0.05 (the decimal form of 5%), resulting in 1.5 grams of the active ingredient needed for the solution.

C (15) YOUR ANSWER

This option miscalculates the required grams. The value of 15 grams would imply a 50% solution (5 grams per 10 mL) rather than the specified 5% w/v. Therefore, this choice does not align with the original prescription.

D (150) YOUR ANSWER

This choice indicates an excessively high amount of active ingredient. For a 5% w/v solution of 30 mL, the calculation clearly shows that only 1.5 grams is necessary. This choice misinterprets the percentage and volume relationship entirely.

Conclusion

To determine the grams of active ingredient in a 5% w/v solution, we apply the percentage to the volume given. In this case, for 30 mL, the calculation confirms that 1.5 grams of the active ingredient is required, making option B the only correct choice. The other options reflect misunderstandings of the percentage calculation related to the solution.

A prescription calls for 30 mL of a 5% w/v solution. How many grams of active ingredient are required?

1.5 grams of active ingredient are required.

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