A pharmacy technician is preparing to compound a prescription that requires 120 mL of a 2% w/v solution of a drug. How many grams of the drug are needed?
To prepare a 120 mL of a 2% w/v solution, 2.4 grams of the drug are needed.
A 2% w/v (weight/volume) solution means there are 2 grams of drug in every 100 mL of solution. To find the total grams required for 120 mL, we can set up a proportion: (2 g / 100 mL) = (x g / 120 mL), which solves to x = 2.4 g.
This choice represents a misunderstanding of the percentage calculation. A 2% solution implies 2 grams per 100 mL, not 0.24 grams for the total volume. Hence, this amount is significantly lower than what is required for 120 mL.
This is the correct answer, as it accurately reflects the calculation of grams required for a 120 mL solution at a 2% concentration. Using the formula, 2 grams in 100 mL leads to 2.4 grams in 120 mL, aligning perfectly with the requirements of the prescription.
Choosing 12 grams indicates a miscalculation based on the percentage concentration. This figure would suggest a much higher concentration than 2%, as it exceeds the logical amount needed for the given volume of solution.
This option represents another significant overestimation of the required drug amount. A 24-gram dosage would imply a 20% solution, which is inconsistent with the specified 2% concentration for the 120 mL volume.
In compounding a 2% w/v solution, the correct calculation reveals that 2.4 grams of the drug are required for 120 mL. Understanding the relationship between percentage concentration and volume is crucial in pharmacy practice, ensuring accurate dosage preparation. Incorrect choices stem from misunderstandings of the calculations involved, highlighting the importance of precise mathematical application in pharmaceutical settings.
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